Optimal. Leaf size=432 \[ \frac {f (a+b x)^{m+1} (c+d x)^{1-m} \left (a^2 d^2 f^2 \left (m^2-5 m+6\right )-2 a b d f \left (6 d e (2-m)-c f \left (3-m^2\right )\right )-2 b d f x (a d f (3-m)-b (6 d e-c f (m+3)))+b^2 \left (c^2 f^2 \left (m^2+5 m+6\right )-12 c d e f (m+2)+30 d^2 e^2\right )\right )}{24 b^3 d^3}-\frac {(a+b x)^{m+1} (c+d x)^{-m} \left (\frac {b (c+d x)}{b c-a d}\right )^m \left (a^3 d^3 f^3 \left (-m^3+6 m^2-11 m+6\right )-3 a^2 b d^2 f^2 \left (m^2-3 m+2\right ) (4 d e-c f (m+1))+3 a b^2 d f (1-m) \left (c^2 f^2 \left (m^2+3 m+2\right )-8 c d e f (m+1)+12 d^2 e^2\right )-\left (b^3 \left (-c^3 f^3 \left (m^3+6 m^2+11 m+6\right )+12 c^2 d e f^2 \left (m^2+3 m+2\right )-36 c d^2 e^2 f (m+1)+24 d^3 e^3\right )\right )\right ) \, _2F_1\left (m,m+1;m+2;-\frac {d (a+b x)}{b c-a d}\right )}{24 b^4 d^3 (m+1)}+\frac {f (e+f x)^2 (a+b x)^{m+1} (c+d x)^{1-m}}{4 b d} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.49, antiderivative size = 431, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {100, 147, 70, 69} \[ -\frac {(a+b x)^{m+1} (c+d x)^{-m} \left (\frac {b (c+d x)}{b c-a d}\right )^m \left (-3 a^2 b d^2 f^2 \left (m^2-3 m+2\right ) (4 d e-c f (m+1))+a^3 d^3 f^3 \left (-m^3+6 m^2-11 m+6\right )+3 a b^2 d f (1-m) \left (c^2 f^2 \left (m^2+3 m+2\right )-8 c d e f (m+1)+12 d^2 e^2\right )+b^3 \left (-\left (12 c^2 d e f^2 \left (m^2+3 m+2\right )-c^3 f^3 \left (m^3+6 m^2+11 m+6\right )-36 c d^2 e^2 f (m+1)+24 d^3 e^3\right )\right )\right ) \, _2F_1\left (m,m+1;m+2;-\frac {d (a+b x)}{b c-a d}\right )}{24 b^4 d^3 (m+1)}+\frac {f (a+b x)^{m+1} (c+d x)^{1-m} \left (a^2 d^2 f^2 \left (m^2-5 m+6\right )-2 a b d f \left (6 d e (2-m)-c f \left (3-m^2\right )\right )+2 b d f x (-a d f (3-m)-b c f (m+3)+6 b d e)+b^2 \left (c^2 f^2 \left (m^2+5 m+6\right )-12 c d e f (m+2)+30 d^2 e^2\right )\right )}{24 b^3 d^3}+\frac {f (e+f x)^2 (a+b x)^{m+1} (c+d x)^{1-m}}{4 b d} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 69
Rule 70
Rule 100
Rule 147
Rubi steps
\begin {align*} \int (a+b x)^m (c+d x)^{-m} (e+f x)^3 \, dx &=\frac {f (a+b x)^{1+m} (c+d x)^{1-m} (e+f x)^2}{4 b d}+\frac {\int (a+b x)^m (c+d x)^{-m} (e+f x) (-a f (2 c f+d e (1-m))+b e (4 d e-c f (1+m))+f (6 b d e-a d f (3-m)-b c f (3+m)) x) \, dx}{4 b d}\\ &=\frac {f (a+b x)^{1+m} (c+d x)^{1-m} (e+f x)^2}{4 b d}+\frac {f (a+b x)^{1+m} (c+d x)^{1-m} \left (a^2 d^2 f^2 \left (6-5 m+m^2\right )-2 a b d f \left (6 d e (2-m)-c f \left (3-m^2\right )\right )+b^2 \left (30 d^2 e^2-12 c d e f (2+m)+c^2 f^2 \left (6+5 m+m^2\right )\right )+2 b d f (6 b d e-a d f (3-m)-b c f (3+m)) x\right )}{24 b^3 d^3}-\frac {\left (a^3 d^3 f^3 \left (6-11 m+6 m^2-m^3\right )-3 a^2 b d^2 f^2 \left (2-3 m+m^2\right ) (4 d e-c f (1+m))+3 a b^2 d f (1-m) \left (12 d^2 e^2-8 c d e f (1+m)+c^2 f^2 \left (2+3 m+m^2\right )\right )-b^3 \left (24 d^3 e^3-36 c d^2 e^2 f (1+m)+12 c^2 d e f^2 \left (2+3 m+m^2\right )-c^3 f^3 \left (6+11 m+6 m^2+m^3\right )\right )\right ) \int (a+b x)^m (c+d x)^{-m} \, dx}{24 b^3 d^3}\\ &=\frac {f (a+b x)^{1+m} (c+d x)^{1-m} (e+f x)^2}{4 b d}+\frac {f (a+b x)^{1+m} (c+d x)^{1-m} \left (a^2 d^2 f^2 \left (6-5 m+m^2\right )-2 a b d f \left (6 d e (2-m)-c f \left (3-m^2\right )\right )+b^2 \left (30 d^2 e^2-12 c d e f (2+m)+c^2 f^2 \left (6+5 m+m^2\right )\right )+2 b d f (6 b d e-a d f (3-m)-b c f (3+m)) x\right )}{24 b^3 d^3}-\frac {\left (\left (a^3 d^3 f^3 \left (6-11 m+6 m^2-m^3\right )-3 a^2 b d^2 f^2 \left (2-3 m+m^2\right ) (4 d e-c f (1+m))+3 a b^2 d f (1-m) \left (12 d^2 e^2-8 c d e f (1+m)+c^2 f^2 \left (2+3 m+m^2\right )\right )-b^3 \left (24 d^3 e^3-36 c d^2 e^2 f (1+m)+12 c^2 d e f^2 \left (2+3 m+m^2\right )-c^3 f^3 \left (6+11 m+6 m^2+m^3\right )\right )\right ) (c+d x)^{-m} \left (\frac {b (c+d x)}{b c-a d}\right )^m\right ) \int (a+b x)^m \left (\frac {b c}{b c-a d}+\frac {b d x}{b c-a d}\right )^{-m} \, dx}{24 b^3 d^3}\\ &=\frac {f (a+b x)^{1+m} (c+d x)^{1-m} (e+f x)^2}{4 b d}+\frac {f (a+b x)^{1+m} (c+d x)^{1-m} \left (a^2 d^2 f^2 \left (6-5 m+m^2\right )-2 a b d f \left (6 d e (2-m)-c f \left (3-m^2\right )\right )+b^2 \left (30 d^2 e^2-12 c d e f (2+m)+c^2 f^2 \left (6+5 m+m^2\right )\right )+2 b d f (6 b d e-a d f (3-m)-b c f (3+m)) x\right )}{24 b^3 d^3}-\frac {\left (a^3 d^3 f^3 \left (6-11 m+6 m^2-m^3\right )-3 a^2 b d^2 f^2 \left (2-3 m+m^2\right ) (4 d e-c f (1+m))+3 a b^2 d f (1-m) \left (12 d^2 e^2-8 c d e f (1+m)+c^2 f^2 \left (2+3 m+m^2\right )\right )-b^3 \left (24 d^3 e^3-36 c d^2 e^2 f (1+m)+12 c^2 d e f^2 \left (2+3 m+m^2\right )-c^3 f^3 \left (6+11 m+6 m^2+m^3\right )\right )\right ) (a+b x)^{1+m} (c+d x)^{-m} \left (\frac {b (c+d x)}{b c-a d}\right )^m \, _2F_1\left (m,1+m;2+m;-\frac {d (a+b x)}{b c-a d}\right )}{24 b^4 d^3 (1+m)}\\ \end {align*}
________________________________________________________________________________________
Mathematica [A] time = 0.74, size = 304, normalized size = 0.70 \[ \frac {(a+b x)^{m+1} (c+d x)^{-m} \left (b^2 (d e-c f)^2 \left (\frac {b (c+d x)}{b c-a d}\right )^m (a d f (m-1)-b c f (m+3)+4 b d e) \, _2F_1\left (m,m+1;m+2;\frac {d (a+b x)}{a d-b c}\right )+f^2 (b c-a d)^2 \left (\frac {b (c+d x)}{b c-a d}\right )^m (a d f (m-3)-b c f (m+3)+6 b d e) \, _2F_1\left (m-2,m+1;m+2;\frac {d (a+b x)}{a d-b c}\right )+2 b f (b c-a d) (d e-c f) \left (\frac {b (c+d x)}{b c-a d}\right )^m (a d f (m-2)-b c f (m+3)+5 b d e) \, _2F_1\left (m-1,m+1;m+2;\frac {d (a+b x)}{a d-b c}\right )+b^3 d^2 f (m+1) (c+d x) (e+f x)^2\right )}{4 b^4 d^3 (m+1)} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
fricas [F] time = 1.10, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (f^{3} x^{3} + 3 \, e f^{2} x^{2} + 3 \, e^{2} f x + e^{3}\right )} {\left (b x + a\right )}^{m}}{{\left (d x + c\right )}^{m}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (f x + e\right )}^{3} {\left (b x + a\right )}^{m}}{{\left (d x + c\right )}^{m}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maple [F] time = 0.23, size = 0, normalized size = 0.00 \[ \int \left (f x +e \right )^{3} \left (b x +a \right )^{m} \left (d x +c \right )^{-m}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (f x + e\right )}^{3} {\left (b x + a\right )}^{m}}{{\left (d x + c\right )}^{m}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (e+f\,x\right )}^3\,{\left (a+b\,x\right )}^m}{{\left (c+d\,x\right )}^m} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
sympy [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: HeuristicGCDFailed} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________